3.3
Hilbert space essentials
The details mathematicians care about and physicists tend to skip. This section covers only the ones that genuinely affect physical conclusions.
Recommended first
After this section you should be able to
- State the three conditions the space of quantum states must satisfy, and why each is necessary
- Explain the definition of the L² space, and why "normalisable" is equivalent to "square-integrable"
- Explain why continuous-spectrum eigenstates do not belong to the space, and how physics handles them
The previous two sections have leaned on “states are vectors” throughout, but a few things were stepped around:
- Does the infinite series converge? Converge to what?
- cannot be normalised — what entitles it to serve as a basis?
- What exactly does “complete” mean?
This section fills those in. Only the parts that affect physical conclusions — for rigorous functional analysis, see a mathematics text.
What the space of states must satisfy
The picture
Condition one: it is a linear space.
States can be added and multiplied by complex numbers, and the result is again a state. This comes straight from the linearity of the Schrödinger equation, and is the mathematical statement of the superposition principle.
Condition two: it has an inner product.
is defined and satisfies the three properties of the previous section. Without an inner product there is no normalisation, no orthogonality, no probability — the Born rule would have nowhere to live.
Condition three: it is complete (in the analyst’s sense).
Every Cauchy sequence converges to an element of the space.
The mathematics
Definition
A space satisfying all three is a Hilbert space, usually written .
The first postulate of quantum mechanics (section 3.7) reads:
The state of a physical system is described by a normalised vector in some Hilbert space.
L²: square-integrable functions
The state space for a single particle in one dimension is
equipped with the inner product .
The picture
What is in , and what is not
In: every bound state, every wave packet, every state that can physically be prepared.
Not in:
- plane waves ()
- ( diverges)
- constants, polynomials, anything that fails to decay
Note that does not require pointwise, nor continuity — only that the integral converges. Physical wavefunctions are additionally required to be smooth enough, but that comes from the Schrödinger equation (which contains second derivatives), not from .
The mathematics
Separability: why the basis can be countable
is separable: it admits a countable orthonormal complete basis.
This property is enormously practical — it guarantees that the “list of numbers” expansion
always works, with no need for uncountably many coefficients.
The infinite well’s and the harmonic oscillator’s are both bases of this kind. Any function can be expanded in harmonic-oscillator eigenstates, even one that has nothing to do with the oscillator.
The continuous spectrum: the “eigenstates” that live outside the space
Now for the question we have been dodging.
The solutions of the position operator’s eigenvalue equation are, in the position basis, . The momentum operator’s eigenstates are plane waves. Neither belongs to .
The picture
Normalisation becomes a δ function
Discrete spectrum:
Continuous spectrum:
This is called δ normalisation. Formally it parallels the discrete case (Kronecker δ replaced by Dirac δ): every formula carries over, with sums traded for integrals.
The mathematics
Mixed spectra
Some Hamiltonians have both a discrete and a continuous spectrum — the finite well of section 2.8 is one: finitely many bound states at negative energy, plus a continuum of scattering states at positive energy.
The completeness relation then reads
Hydrogen works the same way: the discrete ladder , plus the ionised continuum at .
Key formulas
Hilbert space
Where quantum states live; the first postulate
L² space
"Normalisable" = "square-integrable", singled out by the Born rule
δ normalisation
Orthonormality, continuous-spectrum edition
Mixed-spectrum completeness
The finite well and hydrogen both need this form
Self-check3 questions
- 1.
Why is the space of quantum states taken to be "square-integrable functions" rather than something else?
- 2.
Which statements about |x⟩ and |p⟩ are correct? (Select all that apply.)
Select all that apply
- 3.
The "complete" in the definition of a Hilbert space versus the "complete" in the completeness relation Σ|n⟩⟨n| = 1:
What comes next
The space is ready, and the states live inside it. The next question: what operations can be performed on this space?
The answer is linear operators. And among all linear operators, only a very small class earns the title of “observable” — chapter 2’s unexplained decree begins, from the next section on, to become a derivable conclusion.
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