“Schrödinger’s cat is both dead and alive” is the most repeated and most misread sentence in the subject.
The misreading is that it sounds like the cat is in some blurred condition and we merely do not know which. Quantum superposition is precisely not that. This module separates the two.
Superposition is relative to a basis
In the basis this is a superposition: measuring gives half the time each.
In the basis it is an eigenstate of : measuring gives with certainty and no randomness whatsoever.
One state, and changing the basis turns “superposition” into “definite”. So “the system is in a superposition” carries no information unless you say with respect to which basis.
The Bloch sphere: a spin state you can grab with your hand
Every point on the sphere is one pure state. Drag the arrowhead to change it, switch on a magnetic field to watch it precess, pick an axis and measure to watch it collapse.
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Prepare a state
Magnetic field and precession
A magnetic field never "pulls" the spin towards itself. It makes the spin circle around the field direction, and the angle between them never changes.
Measurement
- State vector r⃗
- Precession cone
- Projection onto the measurement axis
- Measurement axis n̂
What to look for
- The formula in the readout is clickable. Click the cos(θ/2) term and θ appears on the sphere; click e^{iφ} and φ appears in the equatorial plane. Every symbol in the formula is some geometric quantity on the sphere.
- Start by dragging θ to 90°. The state lands on the equator, and measuring along z gives 0 and 1 with equal probability. On the sphere, "equal superposition" simply means "standing on the equator".
- Now hold θ fixed and drag only φ: the probabilities along z do not budge. φ is the relative phase — invisible in the z basis, yet it fixes the outcome along x and y. Switch to σx and drag φ again to see the readout move.
- Switch on the field and press play. The angle between the vector and the field never changes; only φ increases steadily. That is Larmor precession.
- Hit "Measure once" a dozen times and watch how random single outcomes are. Then hit "Re-prepare ×200" and watch the measured frequency close in on the theoretical P₊.
✕ "A point on the Bloch sphere is the direction the particle points in space"
It is not. The sphere is state space, not real space. θ = 90° does not mean the spin "lies flat"; it means that measuring along z gives up and down half the time each.
✕ "Measuring again gives a different answer"
It does not. Measurement projects the state onto an eigenstate, so an immediate second measurement along the same axis repeats the first result. To see the statistics you must re-prepare every time — which is exactly what "Re-prepare ×200" does.
Think it through
- Are |ψ⟩ and e^{iα}|ψ⟩ the same point on the sphere? If so, why is the relative phase φ observable while the global phase is not?
- With the field along z and the initial state exactly |0⟩, pressing play changes nothing on screen. Explain that using "an eigenstate only picks up a global phase".
- Set the measurement axis to σx with the state at |0⟩, so P₊ = 0.5. After one measurement the state sits on ±x. Switch back to σz — what are the probabilities now? What does that say about measuring different directions in sequence?
On the Bloch sphere this becomes obvious: the state is a fixed arrow on the sphere, and the measurement basis is an axis you can point wherever you like. When the arrow lies along the axis the outcome is certain; when it is perpendicular it is fifty-fifty. Nothing changed except the question you asked.
Superposition ≠ mixture
Now compare two statements that sound similar:
- A (superposition): the system is in .
- B (mixture): the system is with probability 50% and with probability 50%, and we do not know which.
Measured along , the two give identical statistics: half and half.
Measured along , they could not be more different: A gives every time; B is still fifty-fifty.
In density-matrix form:
The whole difference sits in the off-diagonal elements, the coherences. On the Bloch sphere, A is on the surface at the equator () while B is at the centre ().
Measurements in sequence: order has consequences
Stern-Gerlach in series: measurement is not "having a look"
Every dot that flies past is a real random draw. Set the second analyser to X, measure Z again with the third, and the beam that the first analyser had cleanly filtered out comes back.
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Apparatus
Analyser 1
Analyser 2
Analyser 3
Beam
Counts at the screen
0 absorbed by the blockers. Orthogonal to the previous stage: fifty-fifty — the component filtered out earlier is back
- spin + (along that analyser's axis)
- spin −
- Magnets and blockers
What to look for
- The default is the classic experiment: Z (block lower) → X (block lower) → Z. Note that the last analyser still splits the beam in two, even though the first one passed only "up".
- Set the second analyser to Z as well: only one beam leaves the last one. Measurement is repeatable — along the same axis you can measure as often as you like without changing anything.
- Switch the second analyser back to X and the lower beam returns at once. An X measurement does not read off a property; it genuinely changes the state.
- Keep a single analyser and block nothing: unpolarised silver atoms split half and half. That is what Stern and Gerlach saw in 1922, and it was the first direct evidence that spin takes only two values.
✕ "The first analyser already removed the lower beam, so it should not return"
"Lower" is defined relative to Z. After the X analyser the state is an eigenstate of X, which is once again a superposition in the Z basis. Nothing leaked through the filter; the property itself was redefined.
✕ "The magnetic field bends the spin into a new direction"
The inhomogeneous field supplies a position-dependent force that separates the spin components in space. What actually changes the state is blocking one beam — that is the projection.
Think it through
- Suppose the X analyser blocks nothing and instead recombines both beams without looking at which is which. What does the third Z analyser give? (This is the germ of the quantum eraser.)
- Set all three analysers to Z and block nothing. How many beams reach the screen, and why?
- A silver atom has 47 electrons. Why does the whole thing behave like a single spin-1/2?
Chaining Stern–Gerlach analysers is the sharpest way to see what measurement does:
- Split along , block the lower beam → everything left is ;
- Another → 100% upper. Measurement is repeatable.
- Switch to → fifty-fifty. is a superposition in the basis.
- Add a third analyser along → the lower beam is back.
Step 4 is the point. Step 1 removed “lower” cleanly, and the measurement in step 3 put it back. So the measurement was not passively reading a property; it changed the state.
Algebraically this is just : non-commuting observables share no eigenstates and cannot both be definite.
An honest word about “collapse”
The projection postulate is a rule for calculating: after obtaining eigenvalue , continue with . It has survived every experimental test.
Whether collapse is a physical process is another matter, and the interpretations differ sharply:
| Interpretation | What collapse is |
|---|---|
| Copenhagen | A postulate; the mechanism is not discussed |
| Many worlds | Nothing collapses; there is only unitary evolution and branching |
| Decoherence + epistemic views | Branches lose coherence rapidly; an observer only ever sees one |
| Objective collapse (GRW etc.) | A real stochastic physical process, and therefore falsifiable |
The good news is that all of them predict the same experimental results so far. So you can learn to use the projection postulate as a tool first and pick a side later.
Key formulas
Projection postulate
How to continue after obtaining aₙ
Born probability
Modulus squared, always
Purity test
Strictly less than 1 for a mixed state
Uncertainty
Non-commuting ⇒ not simultaneously definite
Think it through
- In the Bloch scene set the state to and the axis to σx, then measure once. Switch back to σz — what is the probability of now? Map that onto step 4 of the Stern–Gerlach chain.
- and are indistinguishable along . Which axes do you need to measure to tell them apart? (Hint: you have to reconstruct the whole Bloch vector.)
- If “measurement” is just the apparatus becoming entangled with the system, then the apparatus should also end up in a superposition. Why have we never seen a pointer in one? Module 12 gives a partial answer.