11.2
The propagator
Actually compute the "sum over all paths": the full derivation of the free-particle propagator. Its phase turns out to be exactly the classical action, and evolving a Gaussian wave packet with it reproduces wave-packet spreading to the letter.
Recommended first
After this section you should be able to
- Write down the definition of the propagator and relate it to wavefunction evolution, initial conditions, and the composition property
- Define the path integral as a limit of ordinary integrals via time slicing
- Compute the free-particle propagator in full and recognise its phase as the classical action
- Evolve a Gaussian wave packet with the propagator and reproduce the spreading of section 2.10
The last section laid out the manifesto: the amplitude from to is the sum of over all paths. But “sum over all paths” is still just a sentence — there are uncountably many paths, so how do you add them? In this section we actually compute the sum, for the simplest system there is: the free particle ().
First, let us give this “amplitude from to ” its official name.
What the propagator is
The propagator is defined as the probability amplitude to find the particle at at time , given that it was definitely at at time . In the language of chapter 3 it is a matrix element of the evolution operator:
Why does it deserve a name of its own? Because knowing means knowing all of the dynamics. Any initial state is a superposition of position eigenstates, each component propagating independently, so
The propagator is the Schrödinger equation’s “universal solution”: solve for once, and the solution for any initial condition is a single integral away. (Mathematically this is exactly the role of a Green’s function: satisfies the Schrödinger equation with the initial condition as — at the start the particle is at , with zero amplitude anywhere else.)
also has a composition property, inherited directly from the fact that paths can be spliced: going from to an intermediate point and then from to , summed over all intermediate points, equals going from to directly:
This property is about to earn its keep — it lets us chop a long propagation into many short segments.
Defining the path integral properly: time slicing
The picture
How do you index “all paths”? The same old trick as the definite integral: discretise first, take the limit after.
Slice the interval into steps of length . A path is specified by its positions at the slice times, (the endpoints , are fixed), joined by straight segments.
“Sum over all paths” then means: let each range independently over the whole real line — an ordinary -fold integral — and finally take . Last section’s picture of “inserting infinitely many boards that are all slit” becomes a rigorous definition here.
The mathematics
where the action of the zigzag path accumulates segment by segment:
is a per-step normalisation constant (needed for the limit to exist); the derivation below fixes it along the way:
The free particle: computing the integral to the end
The full derivation of the free-particle propagatoradvanced~12 min
With we face a chain of nested Gaussian-type integrals. Only one tool is needed throughout — the Gaussian integral formula (valid for complex too, understood by analytic continuation):
Step 1: the single-step propagator. Over a short interval there is effectively only the straight-line “path”, with amplitude
Step 2: compose two steps. Use the composition formula to merge two steps into one of , integrating over the intermediate point :
Complete the square in inside the exponent:
The second term is independent of and comes outside; the first is killed by the Gaussian formula (set , ):
Key observation: the result has exactly the same shape as the single-step propagator, just with . Choosing makes the prefactor tidy up to exactly — this is how the normalisation constant gets fixed “self-consistently”.
Step 3: induction to N steps. Each intermediate point integrated away leaves the propagator with the same shape and one more time step. After steps (with , writing , ):
The limit is trivial — the shape never depended on in the first place.
Step 4: checks.
- As the exponent oscillates infinitely fast and the prefactor diverges — precisely one representation of . The initial condition checks out.
- Substitute back into the Schrödinger equation and the two sides match term by term (verify it yourself — five lines).
Squaring the books with wave-packet spreading
If the propagator is right, it has to reproduce physics we already know. Section 2.10 computed, by superposing momenta, that a free Gaussian wave packet of initial width spreads with time. Let us redo the calculation with .
Take the initial state to be a Gaussian packet centred at the origin, , and insert it into the evolution formula:
The exponent is again quadratic in — yet another Gaussian integral. Complete the square, integrate, and tidy up:
Word for word the result of section 2.10: spreading time , and the narrower the packet, the faster it spreads. Two languages, one physics — the first concrete audit of their equivalence.
Key formulas
Propagator definition
Position-representation matrix element of the evolution operator; tends to δ(x_b−x_a) as t_b→t_a
Universal evolution formula
Solve for K once and any initial condition is one integral away
Composition property
The basis of time slicing; also called the Chapman-Kolmogorov relation
Free-particle propagator
Phase = classical action m(Δx)²/2t; a universal feature of quadratic Lagrangians
Self-check4 questions
- 1.
The physical meaning of the propagator K(b,a) is:
- 2.
The free-particle propagator satisfies K ∝ e^{iS_cl/ħ}, with the phase exactly the classical action. The condition for this "exactly" to hold is:
- 3.
Which statements about the time-sliced definition of ∫𝒟x(t) are correct? (Select all that apply.)
Select all that apply
- 4.
An electron Gaussian wave packet has initial width σ₀=1.0 nm. What is its spreading time τ=2mσ₀²/ħ in femtoseconds? (m=9.11×10⁻³¹ kg, ħ=1.055×10⁻³⁴ J·s)
fs150% relative tolerance
What comes next
We have now computed a concrete result from the path-integral side and verified that it satisfies the Schrödinger equation. But “verifying one example” is not “proving the two formulations equivalent”. The next section does something more thorough: starting from a short time slice, it derives the Schrödinger equation itself — turning chapter 2’s starting point into a theorem of the path integral.
Section 82 of 106 · use ← → to turn the page